Digital Oscilloscope Readings of Dr Jones Circuit

This new circuit uses a darlington pair of bc547 Low Noise Transistors 50V at 100mA. I am measuring the voltage across a 1 ohm resistor in the ground loop between the battery and the circuit ground. I am using a variable capacitor 50-150pF as well as a 500K ohm variable resistor. The toroid is wound approx 15 turns triple wired the extra winding provides the green led. The Green trace measures the input power. The Yellow trace measure the output voltage across the green led.

This circuit operates at 208kHz and is consuming on average 15-20 milliwatts. The output waveform is approximately 10V peak-to-peak. I am currently constructing a diode bridge to measure the output power.


It turns out that i was measuring the input power incorrectly.
I tried using two similar 1.7 ohm resistors and connected the diode bridge.

The yellow trace represents the output power. Green is the input power.

I must say this looks like an overunity.

Clauss Turtur Zero Point Simulation

Clauss Turtur has written a paper on the zero point energy using mathematical modelling.

The simulation uses a diametric cylinder magnet.
I have replicated the simulation in scilab.


Period: 0.000277 seconds Frequency: 22691.508773
Inductance: 0.37Mass: 0.37 Inertia: 0.00028345

n=600.0;//coil turns
diacoil=0.09;//coil dia
Bo=6.7;//field strength
lcoil=0.01;//length coil
C=0.0053E-6;//capacitance
rm=0.039;//radius magnet
diawire=0.001;//diameter wire
tmag=0.01//thickness of magnet
muo=%pi*4E-7;
epo=8.854E-12;
rho_mag=7.8E3;
A=diacoil*diacoil;
L=muo*A*n*n/lcoil;
fosc=1/sqrt(L*C);
Period=2*%pi/fosc;
printf("Period: %f seconds Frequency: %f\n",Period,fosc);
rho_wire=1.7E-8;
R=200;
Rload=28;
T=20000;
Vc=0;
Q(1)=C*Vc;
ddQ(1)=0;
dQ(1)=0;
phi(1)=0;
dphi(1)=900*%pi;
ddphi(1)=0;
dt=0.000005;
printf("Inductance: %.2f",L);
mass=%pi*rm*rm*tmag*rho_mag;
J=0.5*mass*rm*rm;
printf("Mass: %.2f Inertia: %.8f\n",mass,J);
for t=2:1:T
    
    ddQ(t)=-Q(t-1)/(L*C)-(R+Rload)/L*dQ(t-1);
    ddQ(t)=ddQ(t)+n*Bo*A*sin(phi(t-1))*dphi(t-1)/L;
    
    dQ(t)=dQ(t-1)+(ddQ(t)-R/L*dQ(t-1))*dt;
    Q(t)=Q(t-1)+dQ(t)*dt;
    
    ddphi(t)=-Bo*n*dQ(t)*A/J*sin(phi(t-1)); //torque
    dphi(t)=dphi(t-1)+ddphi(t)*dt;
    phi(t)=phi(t-1)+dphi(t)*dt;
end

The simulation graphs:

3amps Peak-Peak

The magnet is rotating in reverse at -450rpm so an increase of speed will increase to the negative.

Simulation is increasing at 228 ohms resistance any higher the system will slow down.
The trick is to wind the coil bifilar to amplify the Inductance while in keeping the resistance of the coil down as low as possible to achieve over-unity.
Another method would be to use a stronger magnet or higher initial speeds.